I am currently working on a program to filter slow db queries that are stored in a database on the command line.
I would like to search all the commits in all the branches except the one specified and return all the commits that match.
My filter conditions are stored in a database (which is provided for me).
Example:
I have the following entry in the database:
ID key Query
1 ABCDEF select * from example
2 0ABCDE select * from another_example
3 1ABCDE select * from you_get_the_picture
I am now interested in the queries that haven't been fixed in the code yet. So I need to search through the branches with the key as a search filter.
If the key is found in a commit, skip and look up the next. If no match is found, print it to stdout. All the code works fine but I'm having trouble finding the correct git command.
I have the following:
git grep 'ABCDEF' $(git rev-list ^origin/master) | xargs git show -s --format=%N%s
Which should return all commits containing "ABCDEF" in the commit message in all the branches except origin/master.
However, the git command doesn't return anything which is not possible since I know that these commits are there.
Is my git command not correct? Thanks in advance for any pointers.
This is not what you want:
$ git rev-list ^origin/master
$
You asked git rev-list to exclude all revs reachable from origin/master, and to include nothing, so it produces nothing.
This may be what you meant:
$ git rev-list --branches ^origin/master
c2eb39026567499ba9fe0c679766c370462ae26f
Or you might want --tags and/or --remotes as well or instead; or even --all although that includes references like refs/stash.
Of course, that goes inside the git grep commit arguments as you've shown in your example code; it should work from there—except that git grep produces the matching lines, not commit IDs.