How to remain/retain on the same page when using PagedList.mvc

I am using PagedList.Mvc and I have added a nice way to navigate across various pages in an MVC web application. However, when I click on an "edit" or "details" tab and save changes I am sent back to the 1st page. I want to remain on the same page where the changes were made.

Here is the code I have in the controller:

// GET: Item
    public ActionResult Index(int? page)
    {
        var items = db.Items.Include(i => i.PurchaseOrder);
        return View(items.ToList().ToPagedList(page ?? 1, 3));
    }

Here is the code I have in the view:

    @using PagedList;
@using PagedList.Mvc;

@model IPagedList<PurchaseOrders.Models.Item>

@{
    ViewBag.Title = "Index";
}

<h2>Index</h2>

<p>
    @Html.ActionLink("Create New", "Create")
</p>
<table class="table">
    <tr>
        <th>
            @Html.DisplayNameFor(model => model.First().ItemDescription)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().Quantity)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().Price)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().DueDate)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().DateReceived)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().Comments)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.First().PurchaseOrder.PurchaseRequest_)
        </th>
        <th></th>
    </tr>

@foreach (var item in Model) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => item.ItemDescription)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Quantity)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Price)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.DueDate)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.DateReceived)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Comments)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.PurchaseOrder.PurchaseRequest_)
        </td>
        <td>
            @Html.ActionLink("Edit", "Edit", new { id=item.ItemId }) |
            @Html.ActionLink("Details", "Details", new { id=item.ItemId }) |
            @Html.ActionLink("Delete", "Delete", new { id=item.ItemId })
        </td>
    </tr>
}
</table>
@Html.PagedListPager(Model, page => Url.Action("Index", new { page }))

You could pass an additional 'page` parameter to your edit method, for example

In your Index method, add

ViewBag.CurrentPage = page; // or use a view model property

Then your link would be

@Html.ActionLink("Edit", "Edit", new { id=item.ItemId, page = ViewBag.CurrentPage})

Then your edit method

[HttpGet]
public ActionResult Edit(int ID, int page)
{
  ViewBag.CurrentPage = page; // pass current page to edit view

And your edit view

 @using (Html.BeginForm(new { page = ViewBag.CurrentPage })) {

And in you post method

[HttpGet]
public ActionResult Edit(EditModel model, int page)
{
  .... // Save 
  return RedirectToAction("Index", new { page = page });