similar to 1D array declaration :
char arr[]={[0 ... RESERVED_CHARS-1]=' ',[RESERVED_CHARS]='\0'};
please advice how / if possible to declare such 2D array ?
#define SAY_MAX_MSG_LEN 6
#define REP_MAX_MSG_LEN 8
char *var_msg_out[][3]={\
{" Say ",[][0 ... SAY_MAX_MSG_LEN+1]=' ','\0'},\
{" Reply ",[][0 ... REP_MAX_MGS_LEN+1]=' ','\0'}\
};
snprintf(var_msg_out[0][1],SAY_MAX_MSG_LEN,"hello");
printf("%s",var_msg_out[0]);
Thanks !
The only part of what you have is this:
char *var_msg_out[][3]={
{" Say ",[][0 ... SAY_MAX_MSG_LEN+1]=' ','\0'},
^ ???
There is a fundamental issue here: the element after " Say " is a char*
, yet you are trying to assign to it as if it were a char array. The two are not the same thing: your char*
can point to a literal string (like " Say ") with no problem, but you cannot initialize its characters because there is nothing to initialize--only a pointer!
You can fix it this way:
struct foo {
const char* x;
char y[100];
const char* z;
};
struct foo var_msg_out[]={
{" Say ", {[0 ... SAY_MAX_MSG_LEN+1]=' '}, ""},
{" Reply ", {[0 ... REP_MAX_MSG_LEN+1]=' '}, ""}
};