I needed to parse below Date coming from a web service.
2014-09-16T18:05:00.000-05:00
So I tried to created SimpleDateFormat object
SimpleDateFormat simpleDateFormat = new SimpleDateFormat
("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
JavaDocs has below example and format given in the table that matches with my date format.
"yyyy-MM-dd'T'HH:mm:ss.SSSXXX" 2001-07-04T12:08:56.235-07:00
However, I am getting below exception. I use jdk 1.7.0_55. Is there something I am missing ?
Caused by: java.lang.IllegalArgumentException: Illegal pattern character 'X'
at java.text.SimpleDateFormat.compile(SimpleDateFormat.java:768)
at java.text.SimpleDateFormat.initialize(SimpleDateFormat.java:575)
at java.text.SimpleDateFormat.<init>(SimpleDateFormat.java:500)
at java.text.SimpleDateFormat.<init>(SimpleDateFormat.java:475)
Check the version of Java you're using. I bet you're actually using 6.
$ java -version
java version "1.6.0_65"
The XXX format was added in 7. Compare:
http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html