I want to create a boost function object of the following signature:
void (int, boost::uuid);
However, I would like to bind it to a function of the following form:
void (SomeType, boost::uuid)
Where the SomeType argument comes from another function call, so that if I were to call it straight out it would look like:
SomeType myOtherFunction(int);//Prototype
...
myFunction(myOtherFunction(int), myUUID);
In other words, I want the top level function object to completely hide the concept of SomeType and the call to myOtherFunction from the user. Is there a way to do this with one or more boost::function objects created with boost::bind calls?
Functional composition: Live On Coliru
#include <boost/uuid/uuid.hpp>
struct SomeType {};
SomeType myOtherFunction(int) { return SomeType(); }
void foo(SomeType, boost::uuids::uuid) {}
#include <boost/bind.hpp>
#include <boost/function.hpp>
int main()
{
boost::function<void(int, boost::uuids::uuid)> composed;
composed = boost::bind(foo, boost::bind(myOtherFunction, _1), _2);
}
Anyways, in c++11 you'd write [](int i, uuid u) { return foo(myOtherFunction(i), u); }
of course