I created a test using grep
but it does not work in sed
.
grep -P '(?<=foo)bar' file.txt
This works correctly by returning bar
.
sed 's/(?<=foo)bar/test/g' file.txt
I was expecting footest
as output, but it did not work.
GNU sed does not have support for lookaround assertions. You could use a more powerful language such as Perl or possibly experiment with ssed
which supports Perl-style regular expressions.
perl -pe 's/(?<=foo)bar/test/g' file.txt