Say I have 5 vectors:
a <- c(1,2,3)
b <- c(2,3,4)
c <- c(1,2,5,8)
d <- c(2,3,4,6)
e <- c(2,7,8,9)
I know I can calculate the intersection between all of them by using Reduce()
together with intersect()
, like this:
Reduce(intersect, list(a, b, c, d, e))
[1] 2
But how can I find elements that are common in, say, at least 2 vectors? i.e.:
[1] 1 2 3 4 8
It is much simpler than a lot of people are making it look. This should be very efficient.
Put everything into a vector:
x <- unlist(list(a, b, c, d, e))
Look for duplicates
unique(x[duplicated(x)])
# [1] 2 3 1 4 8
and sort
if needed.
Note: In case there can be duplicates within a list element (which your example does not seem to implicate), then replace x
with x <- unlist(lapply(list(a, b, c, d, e), unique))
Edit: as the OP has expressed interest in a more general solution where n >= 2, I would do:
which(tabulate(x) >= n)
if the data is only made of natural integers (1, 2, etc.) as in the example. If not:
f <- table(x)
names(f)[f >= n]
This is now not too far from James solution but it avoids the costly-ish sort
. And it is miles faster than computing all possible combinations.