I am trying, to write a module that when gulp is watching a task, and a Less file changed with some error, it should give a message to the console, but it should not crash the system, which it does no: This is the code I have written:
var onError = function (err) {
console.log(err);
};
gulp.task('styles', function () {
gulp.src('./{views}/**/*.{less}')
.pipe(plumber({
errorHandler: onError
}))
.pipe(less())
.pipe(gulp.dest('build/styles/common.css'));
});
When I run the above code, I get the error below:
'styles' errored after 20 ms
Error in plugin 'plumber'
Message:
Can't pipe to undefined
Yes I have installed gulp-less, and I figured out the solution for this problem aswell: It should be as follow:
gulp.task('mystyle', function () {
gulp.src('build/stylesfiles.less').pipe(plumber()).pipe(less()).
pipe(gulp.dest ('build/styles/assets'));
});
Basically I do not need the Error message, it will give me a default error, which can get my job done.Using the above code will make sure it runs, and gives me my error, but not crash the server....but thank you "Apercu"