Find groups of continuous integers in a list in Java

I have a list of integers placed in order. I want to get groups of consecutive integers as arrays with 1st and last integer of each group.

For example, for (2,3,4,5,8,10,11,12,15,16,17,18,25) I want to get a list with those arrays: [2,5] [8,8] [10,12] [15,18] [25,25]

Here is my code:

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;


public class MyRangesTest {


public static void main(String[] args) {
    //create list of integers
    List<Integer> list=Arrays.asList(2,3,4,5,8,10,11,12,15,16,17,18,25);
    System.out.println("list:" + list);


        //create a list with integers where a new sequense of consecutive integers starts or ends
        List<Integer> sublistsStarsAndEnds= new ArrayList<>();
        sublistsStarsAndEnds.add(list.get(0));//1st line (always in sublistsStarsAndEnds list)
        for (int i=1; i<list.size()-1; i++){
            if (list.get(i)>1+list.get(i-1)){
                sublistsStarsAndEnds.add(list.get(i-1));
                sublistsStarsAndEnds.add(list.get(i));
            }
        }
        sublistsStarsAndEnds.add(list.get(list.size()-1));//last line (always in sublistsStarsAndEnds list)
        System.out.println("sublistsStarsAndEnds: " + sublistsStarsAndEnds);//present the result


        //create list with arrays that represents start and end of each subrange of consequent integers
        List<Integer[]> ranges= new ArrayList<>();
        for (int i=0; i<sublistsStarsAndEnds.size()-1; i=i+2){
            Integer[] currentrange=new Integer[2];
            currentrange[0]=sublistsStarsAndEnds.get(i);
            currentrange[1]=sublistsStarsAndEnds.get(i+1);
            ranges.add(currentrange);//present the result
        }

        //present the result
        String rangestxt="";//create result text
        for (int i=0; i<ranges.size(); i++){
            rangestxt=rangestxt+ranges.get(i)[0]+ " " + ranges.get(i)[1]+ "    ";
         }        
        System.out.println("ranges: " + rangestxt);//present the result


    }

}

This code works in the general case for what I want but when the last sequence has only 1 integer it fails to get the right result.

For example when using this list: (2,3,4,5,8,10,11,12,15,16,17,18,25) instead of getting the ranges [2,5] [8,8] [10,12] [15,18] [25,25] we get the ranges [2,5] [8,8] [10,12] [15,25].

The problem is with the detection of where the ranges start or end. In my code those places are stored in the sublistsStarsAndEnds list. Here instead of getting [2, 5, 8, 8, 10, 12, 15, 15, 25, 25] we get [2, 5, 8, 8, 10, 12, 15, 25]. I tried to correct the code but I without good results.

Any suggestions please?

P.S. Someone wanted to get the result I want and asked a question for Python here "Identify groups of continuous numbers in a list But I don't know Python so I tried my own coding.

try this

 public static void main(String[] args) {
    List<Integer> list=Arrays.asList(2,3,4,5,8,10,11,12,15,16,17,18,19,25);
    List<List<Integer>>lList=new ArrayList<List<Integer>>(); //list of list of integer
    System.out.println("list:" + list);
    int i=0;
    int start=0;
        List<Integer> sList=new ArrayList<Integer>(2);
        for(  i = 1; i <list.size();i++){

           if( list.get(i - 1) + 1 != list.get(i)){
               sList.add(list.get(start));
               sList.add(list.get(i-1));
               lList.add(sList);
               sList=new ArrayList<Integer>(2);
               start=i;

            }

        }
        sList.add(list.get(start));        // for last range
        sList.add(list.get(list.size()-1));
        lList.add(sList);


    System.out.println("Range :"+lList);
}

output :

list:[2, 3, 4, 5, 8, 10, 11, 12, 15, 16, 17, 18, 19, 25]
Range :[[2, 5], [8, 8], [10, 12], [15, 19], [25, 25]]