I was surprised not to find an answer to this question, maybe is something very simple I somehow overlook :
How to get the real size of an UIView after I apply a CGAffineTransform to it?
eg.
my UIView has size 300 x 200, I apply a scaling transform let's say factor 2 both horizontal and vertical, so the UIView now takes 600 x 400 on the screen, but it's bounds and it's layer's bounds are still returning a size of 300 x 200 ... where do I find the real size of the UIView ?
ps. forgot to mention I want to also rotate the uiview. If I apply only scaling CGSizeApplyAffineTransform works great, but when there's also rotation, then it does not work properly.
Edit: drawnonward pointed me in the right direction, I just refined a bit the code to compile and here it is :
UIView* view = (your view being transformed);
CGAffineTransform trans = (view.transform or create a new transformation);
CGRect rect = [view bounds];
CGMutablePathRef path = CGPathCreateMutable();
rect.origin = CGPointZero;
CGPathAddRect(path , &trans , rect);
rect = CGPathGetBoundingBox( path );
CGPathRelease( path );
Now rect.size contains the dimensions of the view with the transformation applied Thanks again to drawnonward
[myView frame] returns the frame of the view as seen by the parent, for layout and relative sizes. [myView bounds] returns the bounds of the view as seen by itself, for drawing. If you have transforms applied to multiple views, you can use convertRect: to or from a view.
Edit:
Maybe something like this.
CGRect rect = [view bounds];
CGPathRef path = CGPathCreateMutable();
rect.origin = CGPointZero;
CGPathAddRect( rect , [view transform] );
rect = CGPathGetBoundingBox( path );
CGPathRelease( path );
The use [view center] to find the position in the superview.