MySQL Insert with While Loop

I'm trying to create a bunch of records in my MySQL database. This is a one time creation so I am not trying to create a stored procedure. Here is my code:

BEGIN
SET i = 2376921001;
WHILE (i <= 237692200) DO
    INSERT INTO `mytable` (code, active, total) values (i, 1, 1);
    SET i = i+1;
END WHILE;
END

Here is the error:

[ERROR in query 1] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SET i = 2376921001 WHILE (i <= 237692200) DO INSERT INTO coupon (couponCod' at line 2 Execution stopped!

I have tried a Declare with the same results. Code below:

BEGIN
DECLARE i INT unsigned DEFAULT 2376921001;
WHILE (i <= 237692200) DO
    INSERT INTO `mytable` (code, active, total) values (i, 1, 1);
    SET i = i+1;
END WHILE;
END

The one other thing I have tried is with @i instead of just i. Same error. Can anyone see what I am doing wrong?

Solution

You cannot use WHILE like that; see: mysql DECLARE WHILE outside stored procedure how?

You have to put your code in a stored procedure. Example:

CREATE PROCEDURE myproc()
BEGIN
    DECLARE i int DEFAULT 237692001;
    WHILE i <= 237692004 DO
        INSERT INTO mytable (code, active, total) VALUES (i, 1, 1);
        SET i = i + 1;
    END WHILE;
END

Fiddle: http://sqlfiddle.com/#!2/a4f92/1

Alternatively, generate a list of INSERT statements using any programming language you like; for a one-time creation, it should be fine. As an example, here's a Bash one-liner:

for i in {2376921001..2376921099}; do echo "INSERT INTO mytable (code, active, total) VALUES ($i, 1, 1);"; done

By the way, you made a typo in your numbers; 2376921001 has 10 digits, 237692200 only 9.