I would like to zeropad a number such that it has 5 digits and get it as a string. This can be done with the following:
unsigned int theNumber = 10;
std::string theZeropaddedString = (boost::format("%05u") % theNumber).str();
However, I do not want to hardcode the number of digits (i.e. the 5 in "%05u").
How can I use boost::format, but specify the number of digits via a variable?
(i.e. put the number of digits in unsigned int numberOfDigits = 5
and then use numberOfDigits with boost::format)
Maybe you can modify the formatter items using standard io manipulators:
int n = 5; // or something else
format fmt("%u");
fmt.modify_item(1, group(setw(n), setfill('0')));
With a given format, you can also add that inline:
std::cout << format("%u") % group(std::setw(n), std::setfill('0'), 42);
#include <boost/format.hpp>
#include <boost/format/group.hpp>
#include <iostream>
#include <iomanip>
using namespace boost;
int main(int argc, char const**) {
std::cout << format("%u") % io::group(std::setw(argc-1), std::setfill('0'), 42);
}
Where it prints
0042
because it is invoked with 4 parameters