iphone-sdk-3.0url-link

Phone Links iPhone SDK - how to return to app

Is it possible to return to my app once a phone link (tel:) has been clicked, and opened using 

[[UIApplication sharedApplication] openURL:xyz]

For example, when the user ends the call?

Thanks

Solution

  • No. Although if you store your state using NSUserDefaults (or other means) you can return to the same point where you left; the user will have to relaunch your app to do this. This approach is recommended in the Human Interface Guidelines.