std::future as a parameter to a function C++

Consider following code

void printPromised(std::future<int> f)
{
    std::cout << f.get() << std::endl;
}

int main()
{
    printPromised(std::async(std::launch::async, [](){ return 8; })); // This works

    auto f = std::async(std::launch::async, [](){ return 8; });
    printPromised(f); // This won't work
}

It says "It is a deleted function". Why is that? Further I need to pass (share) the same promised result which std::async generated to multiple users. That means when someone calls the get() function, I need to pass the same result (I don't need to re generate the result using std::async if it is already generated) and also I need the blocking mechanism which std::future::get has.

There can be only one future. You cannot have multiple copies of the same future. So you need to transfer ownership of the future to the function:

printPromised(std::move(f));
//            ^^^^^^^^^^^^

If you genuinely need shared access to a future, you can construct a shared_future from an ordinary future by calling the share() member function; this behaves similarly to a shared pointer:

auto sf = std::async(std::launch::async, [](){ return 8; }).share();

Now sf can be copied, and all copies wait for the same result, i.e. the wait() calls on all copies may block and will synchronize with the becoming-ready of the result.