I've used .toString(2) to convert an integer to a binary, but it returns a binary only as long as it needs to be (i.e. first bit is a 1).
So where:
num = 2;
num.toString(2) // yields 10.
How do I yield the octet 00000010?
It's as simple as
var n = num.toString(2);
n = "00000000".substr(n.length) + n;
More idiomatically, it can now be written as:
n.padStart(8, '0')
thanks to @DevMultiTech