How to execute url which has xml data as query parameter through Apache HttpClient?

I have a XML like below which is stored as a String in xmlData variable and I need to pass this String to my url in client_data variable -

<?xml version="1.0"?>
<ClientData
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
 xsi:schemaLocation="http://www.google.com model.xsd" 
 xmlns="http://www.google.com"> 
    <client id="100">
        <clock>
                <for>
                    <etc>val(tery) = 1</etc>
                    <while><![CDATA[val(tery)  < 20]]></while>
                </for>
        </clock>
    </model>
</ClientData>

Below is the URL I am hitting on the browser by URL encoding client_data value to get the response back and it works fine.

http://localhost:8080/test_tmp?max_time=30&users=1000&client_data=<?xml version="1.0"?>
<ClientData
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
 xsi:schemaLocation="http://www.google.com model.xsd" 
 xmlns="http://www.google.com"> 
    <client id="100">
        <clock>
                <for>
                    <etc>val(tery) = 1</etc>
                    <while><![CDATA[val(tery)  < 20]]></while>
                </for>
        </clock>
    </model>
</ClientData>

Now I need to do the same thing through Apache HttpClient. What is the best way to do this?

I have got below code but not sure whethere there is any better way to do this? Is there anything I can improve on or some better way of doing it?

public static void main(String[] args) {
    String xmlData = getXMLData();
    String url = generateURL(xmlData);

    HttpClient httpclient = HttpClientBuilder.create().build();
    HttpGet request = new HttpGet(url);

    HttpResponse httpResponse = httpclient.execute(request);

    BufferedReader rd = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent()));

    StringBuffer response = new StringBuffer();
    String line = "";
    while ((line = rd.readLine()) != null) {
        response.append(line);
    }

    // prints response
    System.out.println(response);       
}

private static String generateURL(final String clientData) {
    StringBuilder url = new StringBuilder();
    url.append("http://localhost:8080/test_tmp?max_time=30&users=1000&client_data=");
    url.append(URLEncoder.encode(clientData, "UTF-8"));

    return url.toString();
}

Honestly, I don't think you want to try and pass XML through your URI. There are several things to consider. One, some servers will block long URIs (Google first result: http://www.checkupdown.com/status/E414.html ). Next, you would want to "encode" the URI so it escapes all of your chars that are not ready to be passed raw.

Consider doing a "POST" with the xml the body of the HTTP message.

Hope this helps.