I have found a whole lot of different solutions to this problem, but not all of them work, and a lot of them seem somewhat hacky and inefficient. Basically I have a string of hexadecimal data (i.e. "55 AA 41 2A 00 94 55 AA BB BB 00 FF") which I would like to convert to raw data. What is the best way to do this?
UPDATE: Vicky's solution worked great for me, but I changed it to work with hexadecimal strings that don't have spaces in between and changed the style a bit.
int i = 0;
char *hexString = "55AA412A009455AABBBB00FF"
char *hexPtr = hexString;
unsigned int *result = calloc(strlen(hexString)/2 + 1, sizeof *result);
while (sscanf(hexPtr, "%02x", &result[i++])) {
hexPtr += 2;
if (hexPtr >= hexString + strlen(hexString)) break;
}
return result;
Is the string always the same length?
If so:
char *buf = "55 AA 41 2A 00 94 55 AA BB BB 00 FF";
sscanf(buf, "%x %x %x [repeat as many times as necessary]", &a, &b, &c [etc]);
If not:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main (int argc, char ** argv)
{
char *buf = "55 AA 41 2A 00 94 55 AA BB BB 00 FF";
char *p = buf;
int i = 0, j;
unsigned int *result = calloc(strlen(buf)/3 + 1 * sizeof(int), 1);
if (result)
{
while (sscanf(p, "%02x", &result[i++]))
{
p += 3;
if (p > buf + strlen(buf))
{
break;
}
}
printf("%s\n", buf);
for (j = 0; j < i; j++)
{
printf("%02X ", result[j]);
}
printf("\n");
}
}