I am in a situation where I need to get two different types of vertices using a single query. For example, assume that the graph has the following structure :
Node("User")--Edge("is_member")-->Node("Membership")--Edge("is_member")-->Node("Group")
Assume that the nodes have the following properties:
Now, I need to get all the Membership
nodes that a user is_member
of, along with the corresponding Group
's name
. How do I write a Gremlin query for this?
I am using the Bulbs framework. How do I store the result in a python object?
The following query gives you for user u1
a map with key = Membership-Node
s and value = list of group names of the key membership node
:
m=[:];u1.out('is_member').groupBy(m){it}{it.out('is_member').name}
Output is:
gremlin> m
==>v[m1]=[group1]
==>v[m2]=[group2, group3]
Here the used sample graph:
g = new TinkerGraph()
u1 = g.addVertex('u1')
u2 = g.addVertex('u2')
m1 = g.addVertex('m1')
m2 = g.addVertex('m2')
g1 = g.addVertex('g1')
g2 = g.addVertex('g2')
g3 = g.addVertex('g3')
g.addEdge(u1, m1, 'is_member')
g.addEdge(u1, m2, 'is_member')
g.addEdge(u2, m2, 'is_member')
g.addEdge(m1, g1, 'is_member')
g.addEdge(m2, g2, 'is_member')
g.addEdge(m2, g3, 'is_member')
g1.name = 'group1'
g2.name = 'group2'
g3.name = 'group3'
See also: How do I write a sub-query?
(tested with gremlin2)