I have 10 text files and I want to paste
each file with its pair, such that I have 5 total files.
I tried the following:
for i in 4_1 5_1 6_1 7_1 8_1
do
for j in 4_2 5_2 6_2 7_2 8_2
do
paste ${i}.txt ${j}.txt > ${i}.${j}.txt
done
done
However, this code combines every possible combination instead of just combining the matching pairs.
So I would like file 4_1.txt
to be paired with 4_2.txt
, 5_1.txt
with 5_2.txt
, etc.
I agree with the answer currently proposed by fedorqui in the context of the question currently asked. The below is given only to provide some more general answers.
One more general approach (for bash 4.0 or newer) is to store your pairs in an associative array:
declare -A pairs=( [4_1]=4_2 [5_1]=5_2 [6_1]=6_2 [7_1]=7_2 [8_1]=8_2 )
for i in "${!pairs[@]}"; do
j=${pairs[$i]}
paste "$i.txt" "$j.txt" >"${i}.${j}.txt"
done
Another (compatible with older releases of bash) is to use more than one conventional array:
is=( 4_1 5_1 6_1 7_1 8_1 )
js=( 4_2 5_2 6_2 7_2 8_2 )
for idx in "${!is[@]}"; do
i=${is[$idx]}
j=${js[$idx]}
paste "$i.txt" "$j.txt" >"$i.$j.txt"
done