Let's say I have a series of xml files in this format:
<page>
<header>Page A</header>
<content>blAh blAh blAh</content>
</page>
<page also-include="A.xml">
<header>Page B</header>
<content>Blah Blah Blah</content>
</page>
Using this XSLT:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/page">
<h1>
<xsl:value-of select="header" />
</h1>
<p>
<xsl:value-of select="content" />
</p>
</xsl:template>
</xsl:stylesheet>
I can turn A.xml
into this:
<h1>
Page A
</h1>
<p>
blAh blAh blAh
</p>
But how would I make it also turn B.xml
into this?
<h1>
Page B
</h1>
<p>
Blah Blah Blah
</p>
<p>
blAh blAh blAh
</p>
I know that I need to use document(concat(@also-include,'.xml'))
somewhere, but I'm not sure where.
Oh, and the catch is, I need this to still work if B were to be included in a third file, C.xml
.
Any idea as to how to do this?
It is possible:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="page">
<h1>
<xsl:value-of select="header"/>
</h1>
<p>
<xsl:apply-templates select="." mode="content"/>
</p>
</xsl:template>
<xsl:template match="page" mode="content">
<xsl:value-of select="content"/>
<xsl:if test="@include">
<xsl:apply-templates select="document(@include)" mode="content"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>