I have 3 labels: "A","B","C".
I want to generate a random list with 100 elements, 60% of them are "A", 30% are "B", 10% are "C".
How can I do this? (I am new in python, hope this question is not too silly.)
Edit: My question is slightly different from this question: Generate random numbers with a given (numerical) distribution
Just like in the comment, I want exactly 60% of them are "A", not every element has a 60% probability to be "A". So the numpy.random.choice() is not the solution for me.
If you want exactly 60% to be A, 30% B and 10% C and you know there have to be 100 elements in total, you can do something like the following:
import random
num = 100
prob_a = 0.6
prob_b = 0.3
prob_c = 0.1
As = int(num*prob_a) * 'A'
Bs = int(num*prob_b) * 'B'
Cs = int(num*prob_c) * 'C'
# create a list with 60 As, 30 Bs, and 10 Cs
chars = list(As + Bs + Cs)
random.shuffle(chars)
print("".join(chars))
That'll output something like BAAAAABBCBAABABAAAACAABBAABACAACBAACBBBAAACBAAAABAAABABAAAAABBBABAABAABAACCAABABAAAAAACABBBBCABAAAAA