Yii CButtonColumn updating Database directly

So I have an icon in my CButtonColumn, is it possible to make it in a way that by clicking on that icon, it direct updates a specific field of the record in the database?

For example,

A booking record which has a field Complete. By clicking on the icon, it automatically changes the value of Complete from 0 to 1.

Is it possible to do something like that? If so, how? I tried adding the entire SQL query into the urlExpression like,

Yii::app()->db->createCommand('UPDATE booking SET complete = 1 WHERE id = 1')

But it's not working.

Please help me, Thanks in advance.

UPDATE based on hamed's comment

'changeComplete' => array(
                'imageUrl' => 'images/complete.png',
                'options' => array(
                    'title' => 'Complete',
                    //'style' => 'cursor:pointer; margin: 0 2px;'
                ),
                'url' => 'Yii::app()->createUrl("booking/changeComplete", array("id"=>$data->id))',
                'click' => "function(){
                    $.fn.yiiGridView.update('id', {
                        type:'POST',
                        url:$(this).attr('href'),
                        success:function(data) {
                            $.fn.yiiGridView.update('id');
                        }
                    })
                    return false;
                }",
            ),

in the booking Controller:

public function actionChangeComplete($id)
{
    Yii::app()->db->createCommand('UPDATE booking SET complete = 1 WHERE id = $id');
}

but it is still not working when clicking on the button. Did I do something wrong? Please advise thanks

First thing you should know is database transactions should be executed inside controller, not view. So you should try an action for doing that. Try this inside your gridView

array(
    'class' => 'CButtonColumn',
    'template' => '{changeComplete}',
    'buttons' => array(
        'changeComplete' => array(
            'label' => Your button label',
            'imageUrl' => false,
            'options' => array(
                'title' => 'title of your button',
                'style' => 'cursor:pointer; margin: 0 2px;'
            ),
            'url' => 'Yii::app()->createUrl("test/changeField", array("id"=>$data->id))',
            'click' => "function(){
                        $.fn.yiiGridView.update('gridID', {
                        type:'POST',
                        url:$(this).attr('href'),
                        success:function(data) {
                        $.fn.yiiGridView.update('gridID');
                        }
                    })
                           return false;
                 }
                ",
        ),

    )
),

Now, you need to define actionChangeField inside TestController(controller and action names just are example, you should define an action with suitable name in suitable controller)

public function actionChangeField($id)
{
      Yii::app()->db->createCommand('UPDATE booking SET complete = 1 WHERE id = $id')->execute();
}

Finally, replace "gridID" with id of your grid(without # sign).