Alright so this is the ever so popular bomb lab and I am currently on phase 5 and I'm only stuck on two lines. Here's the assembly code:
Dump of assembler code for function phase_5:
0x08048e29 <+0>: push %ebx
0x08048e2a <+1>: sub $0x18,%esp
0x08048e2d <+4>: mov 0x20(%esp),%ebx
0x08048e31 <+8>: mov %ebx,(%esp)
0x08048e34 <+11>: call 0x804908b <string_length>
0x08048e39 <+16>: cmp $0x6,%eax
0x08048e3c <+19>: je 0x8048e43 <phase_5+26>
0x08048e3e <+21>: call 0x80493a5 <explode_bomb>
0x08048e43 <+26>: mov $0x0,%edx
0x08048e48 <+31>: mov $0x0,%eax
0x08048e4d <+36>: movzbl (%ebx,%eax,1),%ecx
0x08048e51 <+40>: and $0xf,%ecx
0x08048e54 <+43>: add 0x804a4a0(,%ecx,4),%edx
0x08048e5b <+50>: add $0x1,%eax
0x08048e5e <+53>: cmp $0x6,%eax
0x08048e61 <+56>: jne 0x8048e4d <phase_5+36>
=> 0x08048e63 <+58>: cmp $0x42,%edx
0x08048e66 <+61>: je 0x8048e6d <phase_5+68>
0x08048e68 <+63>: call 0x80493a5 <explode_bomb>
0x08048e6d <+68>: add $0x18,%esp
0x08048e70 <+71>: pop %ebx
0x08048e71 <+72>: ret
---Type <return> to continue, or q <return> to quit---
End of assembler dump.
Here's a barebones look when I run it through a decompiler:
void phase_5(__size8 *param1) {
__size32 eax; // r24
int eax_1; // r24{48}
unsigned int ecx; // r25
__size32 edx; // r26
eax = string_length(param1);
if (eax != 6) {
explode_bomb();
}
edx = 0;
eax = 0;
do {
eax_1 = eax;
ecx = *(unsigned char*)(param1 + eax_1);
edx += array.3142[(ecx & 0xf)];
eax = eax_1 + 1;
} while (eax_1 + 1 != 6);
if (edx != 66) {
explode_bomb();
}
return;
}
So the general synopsis of this phase is that the string input needs to be 6 characters, then it goes through a do while loop where it takes the string and turns it into a number through its algorithm and then compares it if it's 66 at the end. My questions is what do these two lines do:
ecx = (unsigned char)(param1 + eax_1); edx += array.3142[(ecx & 0xf)];
More specifically the first one. The second line &s the value of the first line with 15 which essentially gives the last 4 bits of ecx but what does adding the string (param1) with the loop counter (eax_1) do? Also is this the line that converts each character in the string into a number? Any help would be greatly appreciated!
what does adding the string (param1) with the loop counter (eax_1) do?
That's just array indexing. It gives you the address of the appropriate character. ecx = *(unsigned char*)(param1 + eax_1) is basically ecx = param1[eax_1].
As you say, the code loops through all 6 letters, keeps the low 4 bits of the ascii code and uses that to index a hardcoded lookup table. The selected values from said lookup table are summed up, and that's your result which has to be 0x42.