How do I swap the last column in a csv file to be the first column? + awk

How do I swap the last column in a csv file to be the first column?

I am thinking of using awk but not sure?

awk -F, '{print $1,$2}' filename

OR is sed a better option?

For an arbitrary number of columns, you can do:

awk 'BEGIN {OFS=FS=",";} {temp=$NF; $NF = ""; sub(",$", ""); print temp, $0}' filename

• OFS=FS="," sets the output and input field separators to comma.
• temp = $NF saves the original contents of the last column in a variable.
• $NF = '' empties the last column in the input.
• sub(",$", "") gets rid of the extra comma left by that
• print temp, $0 prints the saved last column followed by the rest of the input.

If you know how many columns there are, it would be nice if we could do it like this:

cut -d, -f9,1-8 infile > outfile

But it doesn't work, see Rearrange columns using cut for the reason.