Django error reporting handles uncaught exceptions by sending an email, and (optionally) shows user a nice 500 error page.
This works very well, but in a few instances I'd like to allow users to continue with their business uninterrupted, but still have Django send me the email error report about the exception.
So basically: can I manually send email error report even if I catch the exception?
Of course, I'd like to avoid manually generating the error report email.
You can use the following code to send manually an email about a request
and an exception e
:
import sys
import traceback
from django.core import mail
from django.views.debug import ExceptionReporter
def send_manually_exception_email(request, e):
exc_info = sys.exc_info()
reporter = ExceptionReporter(request, is_email=True, *exc_info)
subject = e.message.replace('\n', '\\n').replace('\r', '\\r')[:989]
message = "%s\n\n%s" % (
'\n'.join(traceback.format_exception(*exc_info)),
reporter.filter.get_request_repr(request)
)
mail.mail_admins(
subject, message, fail_silently=True,
html_message=reporter.get_traceback_html()
)
You can test it in a view like this:
def test_view(request):
try:
raise Exception
except Exception as e:
send_manually_exception_email(request, e)