I'm facing a problem with Alfresco and Python : I want to upload a new file directly with Python. Each time I try I get a HTTP 500 error with no details ...
I first try with CURL just to be sure that it works and the file is uploaded without problems.
I used the following curl command line:
url -X POST -uadmin:admin "http://localhost:8080/alfresco/service/api/upload" -F filedata=@/tmp/eeeeee.pdf -F siteid=test -F containerid=documentLibrary
In my Python script I tried PyCurl and now the simple urllib. I think the problem come from the way the file is given as parameter.
Python code using PyCurl:
c = pycurl.Curl()
params = {'containerid': 'documentLibrary', 'siteid': 'test', 'filedata': open('/tmp/eeeeee.pdf', 'rb')}
c.setopt(c.URL, 'http://localhost:8080/alfresco/service/api/upload')
c.setopt(c.POST, 1)
c.setopt(c.POSTFIELDS, urllib.urlencode(params))
c.setopt(c.USERPWD, 'admin:admin')
c.perform()
This code sample leads to :
{
"code" : 500,
"name" : "Internal Error",
"description" : "An error inside the HTTP server which prevented it from fulfilling the request."
},
"message" : "04200017 Unexpected error occurred during upload of new content."
Does someone know how to achieve that?
You can use the very simple library Requests.
import json
import requests
url = "http://localhost:8080/alfresco/service/api/upload"
auth = ("admin", "admin")
files = {"filedata": open("/tmp/foo.txt", "rb")}
data = {"siteid": "test", "containerid": "documentLibrary"}
r = requests.post(url, files=files, data=data, auth=auth)
print(r.status_code)
print(json.loads(r.text))
Output:
200
{'fileName': 'foo.txt',
'nodeRef': 'workspace://SpacesStore/37a96447-44b0-4aaa-b6ff-98dae1f12a73',
'status': {'code': 200,
'description': 'File uploaded successfully',
'name': 'OK'}}