I have JS code for jqxWindow
which works only one time:
$(document).ready(function () {
$("#jqxwindow1 ").jqxWindow({ height: 800, width: 1212, maxWidth: 1600, maxHeight: 900, animationType: 'none', theme: 'fresh', autoOpen: false });
$("#jqxwindow2 ").jqxWindow({ height: 800, width: 1212, maxWidth: 1600, maxHeight: 900, animationType: 'none', theme: 'fresh', autoOpen: false });
$("#jqxwindow3 ").jqxWindow({ height: 800, width: 1212, maxWidth: 1600, maxHeight: 900, animationType: 'none', theme: 'fresh', autoOpen: false });
$("#jqxwindow4 ").jqxWindow({ height: 800, width: 1212, maxWidth: 1600, maxHeight: 900, animationType: 'none', theme: 'fresh', autoOpen: false });
$("#jqxwindow5 ").jqxWindow({ height: 800, width: 1212, maxWidth: 1600, maxHeight: 900, animationType: 'none', theme: 'fresh', autoOpen: false });
$('div[id^="test"] p').click(function() {
var string = "#jqxwindow" + $(this).text().split('|')[0];
//alert("The window is opened : " + string);
var opened = $(string).jqxWindow('isOpen');
var action = 'close';
if (opened == false)
action = 'open';
$(string).jqxWindow(action);
$(string).jqxWindow('bringToFront');
});
});
I was searching but every solution didn't work for me.
LE:
Uncaught TypeError: $(...).jqxWindow is not a function
on line
var opened = $(string).jqxWindow('isOpen');
I resolved: Just put before (document) jQuery and in function put argument $. ex. down:
jQuery(document).ready(function ($) {
//function code
}
And now it's work.