How to convert English numbers in a string to Persian/Farsi or Arabic numbers in Objective-C?

I have an English (Latin) string that may or may not have numbers. But I want those numbers to be printed on screen as Persian (Farsi) numbers.

For example, if NSString *foo = @"a string with numbers 1 2 3;"

then output should be a string with numbers ۱۲۳

The code I'm using right now is:

-(NSString *)convertEnNumberToFarsi:(NSString *) number{
    NSString *text;
    NSDecimalNumber *someNumber = [NSDecimalNumber decimalNumberWithString:number];
    NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
    NSLocale *gbLocale = [[NSLocale alloc] initWithLocaleIdentifier:@"fa"];
    [formatter setLocale:gbLocale];
    text = [formatter stringFromNumber:someNumber];
    return text;
}

This method only converts a string that is only in numbers, but as mentioned above I want to convert any string that may or may not have numbers in it.

How can I achieve this?

The simple way:

NSDictionary *numbersDictionary = @{@"1" : @"۱", @"2" : @"۲", @"3" : @"۳", @"4" : @"۴", @"5" : @"۵", @"6" : @"۶", @"7" : @"۷", @"8" : @"۸", @"9" : @"۹",@"0" : @"٠"};
for (NSString *key in numbersDictionary) {
  str = [str stringByReplacingOccurrencesOfString:key withString:numbersDictionary[key]];
}

Other solution more flexible with locale:

NSNumberFormatter *formatter = [NSNumberFormatter new];
formatter.locale = [NSLocale localeWithLocaleIdentifier:@"ar"];
for (NSInteger i = 0; i < 10; i++) {
  NSNumber *num = @(i);
  str = [str stringByReplacingOccurrencesOfString:num.stringValue withString:[formatter stringFromNumber:num]];
}

Note: this code wrote without IDE, it can be with syntax errors.