Use a function in Powershell replace

I'm trying to replace part of a string in Powershell. However, the replacement string is not hardcoded, it's calculated from a function:

$text = "the image is -12345-"
$text = $text -replace "-(\d*)-", 'This is the image: $1'
Write-Host $text

This gives me the correct result: "This is the image: 12345"

Now, I want to include the base64 encoded image. I can read the image from the id. I was hoping the following would work, but it doesn't:

function Get-Base64($path)
{
    [convert]::ToBase64String((get-content $path -encoding byte))
}
$text -replace "-(\d*)-", "This is the image: $(Get-Base64 '$1')"

The reason that it doesn't work, is because it first passes $1 (the string, not the value of $1) to the function, executes it and only then does it do the replace. What I want to do is

• Find the occurrence of the pattern
• Replace each occurence with the pattern
• For each replace:
• Pass the capture group to the function
• Use the value of the capture group to get the base64 image
• inject the base64 image into the replacement

You can use the static Replace method from the [regex] class:

[regex]::Replace($text,'-(\d*)-',{param($match) "This is the image: $(Get-Base64 $match.Groups[1].Value)"})

Alternatively you can define a regex object and use the Replace method of that object:

$re = [regex]'-(\d*)-'
$re.Replace($text, {param($match) "This is the image: $(Get-Base64 $match.Groups[1].Value)"})

For better readability you could define the callback function (the scriptblock) in a separate variable and use that in the replacement:

$callback = {
  param($match)
  'This is the image: ' + (Get-Base64 $match.Groups[1].Value)
}

$re = [regex]'-(\d*)-'
$re.Replace($text, $callback)