[SOLVED] Kotlin 'when' statement vs Java 'switch'

Kotlin 'when' statement vs Java 'switch'

Pattern matching in Kotlin is nice and the fact it does not execute the next pattern match is good in 90% of use cases.

In Android, when database is updated, we use Java switch property to go on next case if we do not put a break to have code looking like that:

switch (oldVersion) {
    case 1: upgradeFromV1();
    case 2: upgradeFromV2(); 
    case 3: upgradeFromV3();
}

So if someone has an app with version 1 of the DB and missed the app version with DB v2, he will get all the needed upgrade code executed.

Converted to Kotlin, we get a mess like:

when (oldVersion) {
    1 -> {
        upgradeFromV1()
        upgradeFromV2()
        upgradeFromV3()
    }
    2 -> {
        upgradeFromV2()
        upgradeFromV3()
    }
    3 -> {
        upgradeFromV3()
    }
}

Here we have only 3 versions, imagine when DB reaches version 19.

Anyway to makes when acting in the same way then switch? I tried to continue without luck.

Solution

Simple but wordy solution is:

if (oldVersion <= 1) upgradeFromV1()
if (oldVersion <= 2) upgradeFromV2()
if (oldVersion <= 3) upgradeFromV3()

Another possible solution with function references:

fun upgradeFromV0() {}
fun upgradeFromV1() {}
fun upgradeFromV2() {}
fun upgradeFromV3() {}

val upgrades = arrayOf(::upgradeFromV0, ::upgradeFromV1, ::upgradeFromV2, ::upgradeFromV3)

fun upgradeFrom(oldVersion: Int) {
    for (i in oldVersion..upgrades.lastIndex) {
        upgrades[i]()
    }
}