I'm writing audio from an external decoding library on OS X to an AIFF file, and I am able to swap the endianness of the data with OSSwapInt32().
The resulting AIFF file (16-bit PCM stereo) does play, but the left and right channels are swapped.
Would there be any way to swap the channels as I am writing each buffer?
Here is the relevant loop:
do
{
xmp_get_frame_info(writer_context, &writer_info);
if (writer_info.loop_count > 0)
break;
writeModBuffer.mBuffers[0].mDataByteSize = writer_info.buffer_size;
writeModBuffer.mBuffers[0].mNumberChannels = inputFormat.mChannelsPerFrame;
// Set up our buffer to do the endianness swap
void *new_buffer;
new_buffer = malloc((writer_info.buffer_size) * inputFormat.mBytesPerFrame);
int *ourBuffer = writer_info.buffer;
int *ourNewBuffer = new_buffer;
memset(new_buffer, 0, writer_info.buffer_size);
int i;
for (i = 0; i <= writer_info.buffer_size; i++)
{
ourNewBuffer[i] = OSSwapInt32(ourBuffer[i]);
};
writeModBuffer.mBuffers[0].mData = ourNewBuffer;
frame_size = writer_info.buffer_size / inputFormat.mBytesPerFrame;
err = ExtAudioFileWrite(writeModRef, frame_size, &writeModBuffer);
} while (xmp_play_frame(writer_context) == 0);
This solution is very specific to 2 channel audio. I chose to do it at the same time you're looping to change the byte ordering to avoid an extra loop. I'm going through the loop 1/2 the number and processing two samples per iteration. The samples are interleaved so I copy from odd sample indexes into even sample indexes and vis-a-versa.
for (i = 0; i <= writer_info.buffer_size/2; i++)
{
ourNewBuffer[i*2] = OSSwapInt32(ourBuffer[i*2 + 1]);
ourNewBuffer[i*2 + 1] = OSSwapInt32(ourBuffer[i*2]);
};
An alternative is to use a table lookup for channel mapping.