I am making an application with radius search, here is the example I learned from
https://developers.google.com/maps/articles/phpsqlsearch_v3#findnearsql
In my case
I do
SELECT (3959 * acos(cos(radians(-37.814107)) * cos(radians(lat)) * cos(radians(lng) - radians(144.96327999999994)) + sin(radians(-37.814107)) * sin(radians(lat)))) AS distance;
when lat = -37.8141070000, lng = 144.9632800000
SELECT (3959 * acos(cos(radians(-37.814107)) * cos(radians(-37.8141070000)) * cos(radians(144.9632800000) - radians(144.96327999999994)) + sin(radians(-37.814107)) * sin(radians(-37.8141070000)))) AS distance;
MySQL output the distance as NULL, why? Did I do something wrong?
How I fix it? Sorry I am really NOT good at math.
Basic SQL query
SELECT * FROM table
You must have a MySql table in your query with lat & lng as fields. ie
SELECT (3959 * acos(cos(radians(-37.814107))
* cos(radians(lat)) * cos(radians(lng) - radians(144.96327999999994))
+ sin(radians(-37.814107))
* sin(radians(lat)))) AS distance FROM table;