I know I can use this to get the full file path
os.path.dirname(os.path.realpath(__file__))
But I want just the name of the folder, my scrip is in. SO if I have my_script.py and it is located at
/home/user/test/my_script.py
I want to return "test" How could I do this?
Thanks
import os
os.path.basename(os.path.dirname(os.path.realpath(__file__)))
Broken down:
currentFile = __file__ # May be 'my_script', or './my_script' or
# '/home/user/test/my_script.py' depending on exactly how
# the script was run/loaded.
realPath = os.path.realpath(currentFile) # /home/user/test/my_script.py
dirPath = os.path.dirname(realPath) # /home/user/test
dirName = os.path.basename(dirPath) # test