Value also contains some letters
I have search through so many questions but I couldn't find it.
I have string like this:
Ab2cds value=284t810 shfn4wksn value=39h1047 hs2krj8dne value=3700p134
What I want to do is get all values only in output like:
284t810 39h1047 3700p134
I used substr
and strpos
combine to get value but it only removes portion of data ahead of first "value=" so output is like:
284t810 shfn4wksn value=39h1047 hs2krj8dne value=3700p134
I just want to delete everything else and keep only numbered value which is after "value=".
use this code:
with this code you get any strings that they are after value=
.
I think this is the easiest solution.
$str = 'b2cds value=284t810 shfn4wksn value=39h1047 hs2krj8dne value=3700p134';
preg_match_all('#value=([^\s]+)#', $str, $matches);
echo implode(' ', $matches[1]);
@Kesh : \s
means space. [^\s]
means everything except space. and +
means at least one char. and the ()
around it is for selecting the string so we can use it after the operation. ([^\s]+)
means select everything except space and put them to the $matches