I know I am supposed to put '/o' at end of character array but When I want to print "printf ("%s\n", kk);" , it gives "abcdepqrst". Why is this happening? This is the program I am executing.
#include<stdio.h>
int main()
{
char kk[]={'a','b','c','d','e'};
char s[]="pqrst";
printf("%s\n",s);
printf("%s\n",kk);
}
Output:
pqrst
abcdepqrst
I tried reversing the order in which I declare the array by declaring array 's' before array 'kk' here, ideone link, but I am still getting the same output. I think it has something do with how ideone allocates memory to variables.
#include<stdio.h>
int main()
{
char s[]="pqrst";
char kk[]={'a','b','c','d','e'};
printf("%s\n",s);
printf("%s\n",kk);
}
Output:
pqrst
abcdepqrst
The printf() function expects a null terminated string but you are passing a character array with no null terminator. Try changing your array to:
char kk[]={'a','b','c','d','e','\0'};
When you use string literal syntax to initialize your s array, the null terminator is automatically added:
char s[] = "pqrst"; // s is {'p','q','r','s','t','\0'}