php

Different HTML files in one PHP file


I have one PHP file. And I have multiple HTML files.

At first I show the first HTML file when the PHP file is loaded. So I included the code from "page1.html" into the PHP file.

Now after clicking the submit button and the validation on this PHP file I want to replace the current HTML file with another one.

But when I include page2.html after the validation was successful, it shows just the body content of the page2.html file under the "page1.html" content.

I want to replace the entire html file, not just a few elements. And it has to be in the PHP file where the first file was included too.

Is there any solution?

<?php



include 'page1.html';


// define variables and initialize with empty values

$Content "";
$Error = "";

if ($_SERVER["REQUEST_METHOD"] == "POST")
    {
    if (!isset($_POST["name"]))
        {
        $Error = "There is an error.";
        }
      else
         {
        $Content = $_POST["content"];
        }


    if (empty($Error))
        {

        include 'page2.html';


        }
    }

?>

Solution

  • Use condition in your PHP file

    <?php
    
    if (isset($_POST))
    {
        include 'page2.html';
    }
    else
    {
        include 'page1.html';
    }