goconcurrencytimeout

Timeout for WaitGroup.Wait()


What is an idiomatic way to assign a timeout to WaitGroup.Wait() ?

The reason I want to do this, is to safeguard my 'scheduler' from potentially awaiting an errant 'worker' for ever. This leads to some philosophical questions (i.e. how can the system reliably continue once it has errant workers?), but I think that's out of scope for this question.

I have an answer which I'll provide. Now that I've written it down, it doesn't seem so bad but it still feels more convoluted than it ought to. I'd like to know if there's something available which is simpler, more idiomatic, or even an alternative approach which doesn't use WaitGroups.


Solution

  • Mostly your solution you posted below is as good as it can get. Couple of tips to improve it:

    I would also create a helper / utility function wrapping this functionality. Note that WaitGroup must be passed as a pointer else the copy will not get "notified" of the WaitGroup.Done() calls. Something like:

    // waitTimeout waits for the waitgroup for the specified max timeout.
    // Returns true if waiting timed out.
    func waitTimeout(wg *sync.WaitGroup, timeout time.Duration) bool {
        c := make(chan struct{})
        go func() {
            defer close(c)
            wg.Wait()
        }()
        select {
        case <-c:
            return false // completed normally
        case <-time.After(timeout):
            return true // timed out
        }
    }
    

    Using it:

    if waitTimeout(&wg, time.Second) {
        fmt.Println("Timed out waiting for wait group")
    } else {
        fmt.Println("Wait group finished")
    }
    

    Try it on the Go Playground.