Fill array with numbers adding up to a nominated total without exceeding item maximum

I need to fill an array with numbers, a few examples:

• nbreParChargement = 4; For 10
  Expected output: $niveaux = array(4,4,2); 4+4+2 = 10

• nbreParChargement = 6; For 14
  Expected output: $niveaux = array(6,6,2); 6+6+2 = 14

• nbreParChargement = 16; For 13
  Expected output: $niveaux = array(13); 13 = 13

• nbreParChargement = 4; For 30
  Expected output: $niveaux = array(4,4,4,4,4,4,4,2); 4+4+4+4+4+4+4+2 = 30

I tried to resolve this but I don't know the perfect solution:

function chargement($nbre, $nbreParChargement) {
    $niveaux = array();
    for($i=0; $i<=$nbre; $i++){
        $niveaux[$i] = $i + $nbreParChargement;         
    }
}

Another implementation, with two lines of code, for php >= 5.6:

function chargement($nbre, $nbreParChargement){
    $niveaux = array_fill(0, floor($nbre/$nbreParChargement), $nbreParChargement);
    $niveaux[] = $nbre - array_sum($niveaux);

    return $niveaux;
}

var_dump(chargement(10, 4));
var_dump(chargement(14, 6));
var_dump(chargement(13, 16));
var_dump(chargement(30, 4));

array_fill fills an array with $nbre/$nbreParChargement entries with $nbreParChargement's value. The last value are the difference between $nbre and the sum of the other elements, given by $nbreParChargement * floor($nbre/$nbreParChargement), that will be always > 0.

Demo.

This work only for php >= 5.6 because array_fill accepts 0 as num only from that version. Previously, num was required to be greater than zero.

So, for any version of php:

function chargement($nbre, $nbreParChargement){
    $niveaux = array();
    if ($n = floor($nbre/$nbreParChargement)) {
        $niveaux = array_fill(0, $n, $nbreParChargement);
    }

    $niveaux[] = $nbre - array_sum($niveaux);
    return $niveaux;
}

Demo.