Getting only element from a single-element list in Python?

When a Python list is known to always contain a single item, is there a way to access it other than:

mylist[0]

You may ask, 'Why would you want to?'. Curiosity alone. There seems to be an alternative way to do everything in Python.

Raises exception if not exactly one item:

Sequence unpacking:

singleitem, = mylist
# Identical in behavior (byte code produced is the same),
# but arguably more readable since a lone trailing comma could be missed:
[singleitem] = mylist

Rampant insanity, unpack the input to the identity lambda function:

# The only even semi-reasonable way to retrieve a single item and raise an exception on
# failure for too many, not just too few, elements as an expression, rather than a
# statement, without resorting to defining/importing functions elsewhere to do the work
singleitem = (lambda x: x)(*mylist)

All others silently ignore spec violation, producing first or last item:

Explicit use of iterator protocol:

singleitem = next(iter(mylist))

Destructive pop:

singleitem = mylist.pop()

Negative index:

singleitem = mylist[-1]

Set via single iteration for (because the loop variable remains available with its last value when a loop terminates):

for singleitem in mylist: break

There are many others (combining or varying bits of the above, or otherwise relying on implicit iteration), but you get the idea.