I have seen in plenty of websites the common use of MarkupBuilder xml creator. For example:
def xmlWriter = new StringWriter()
def xmlMarkup = new MarkupBuilder(xmlWriter)
xmlMarkup.movie(id: "2", "the godfather")
println(xmlWriter.toString())
Will give something like this:
<movie id='2'>the godfather</movie>
My question is: ¿Is there a good way to use MarkupBuilder to compose an xml using variables taken from a method?
I have manage to add the root access with this code:
createXml(root){
def xmlWriter = new StringWriter()
def xmlMarkupBuilder = new MarkupBuilder(xmlStringWriter)
xmlMarkupBuilder.createNode(root)
xmlMarkupBuilder.nodeCompleted(null,root)
}
But I'm pretty sure there must be another clean way to do it. How can I add a new node if I only know the name of the parent node?
I ended up doing this with java DocumentBuilder,
XmlData(xmlPath, rootNodeName){
this.xmlPath = xmlPath
xmlDoc = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument()
def rootNode=xmlDoc.createElement(rootNodeName)
xmlDoc.appendChild(rootNode)
}
def addNode(parentNodeName,nodeName,nodeValue,attributes){
def newNode = xmlDoc.createElement(nodeName)
if(nodeValue!=null){
def newTextNode = xmlDoc.createTextNode(nodeValue)
newNode.appendChild(newTextNode)
}
if(attributes!=null){
attributes.each{key,value ->
newNode.setAttribute($key,$value)
}
}
def nodeList = xmlDoc.getElementsByTagName(parentNodeName)
nodeList.item(nodeList.getLength()-1).appendChild(newNode)
}
but if there is a cleaner way to do this with MarkupBuilder or MarkupBuilderHelper, I would preffer to use that one. The code I would like to get is:
Input:
def xmlWriter = new XmlWriter("rootNode")
xmlWriter.addNode("rootNode","",null)
xmlWriter.addNode("rootNode","child2",null)
xmlWriter.addNode("child1","child11","text1")
xmlWriter.addNode("child1","child12","text2")
xmlWriter.addNode("child2","child21","text3")
xmlWriter.addNode("child2","child22","text4")
Methods:
class XmlWriter{
createXml(root){
def xmlWriter = new StringWriter()
def xmlMarkupBuilder = new MarkupBuilder(xmlStringWriter)
xmlMarkupBuilder.createNode(root)
xmlMarkupBuilder.nodeCompleted(null,root)
}
def addNode(parentNodeName,nodeName,nodeValue,attributes){
???
}
}
Output:
<rootNode>
<child1>
<child11>test1</child11>
</child12>test2</child12>
</child1>
<child2>
<child21>test3</child21>
</child22>test4</child22>
</child2>
</rootNode>
Note: I don't take into account that could exist several items in nodeList items because in my xml this is not possible at the present moment.
Here's one method to do what I think you want...
Given some XML:
def xml = '''<root>
| <node>
| <anotherNode some="thing">
| Woo
| </anotherNode>
| <stuff>
| </stuff>
| <node>
| </node>
| <anotherNode some="thing">
| Woo
| </anotherNode>
| <stuff>
| </stuff>
| </node>
|</root>'''.stripMargin()
and given the name of the parent node, the name of the new child node, it's attributes and text content:
def parentName = 'stuff'
def nodeName = 'things'
def nodeContent = 'text'
def attributes = [ tim: 'yates' ]
We can parse the XML with XmlParser
import groovy.xml.*
def root = new XmlParser().parseText(xml)
And then find all nodes called parentName
and append a new node to each of them:
root.'**'.findAll { it.name() == parentName }
.each {
it.appendNode(new Node(it, nodeName, attributes, nodeContent))
}
Then, printing out the xml should show they're there:
println XmlUtil.serialize(root)