How can I split the given String in Swift into groups with given length, reading from right to left?
For example, I have string 123456789 and group length of 3. The the string should be divided into 3 groups: 123, 456, 789. String 1234567 will be divided into 1, 234, 567
So, can you write some nice code in Swift:
func splitedString(string: String, length: Int) -> [String] {
}
BTW tried function split(), but as I understand it works only with finding some symbol
Just to add my entry to this very crowded contest (SwiftStub):
func splitedString(string: String, length: Int) -> [String] {
var result = [String]()
for var i = 0; i < string.characters.count; i += length {
let endIndex = string.endIndex.advancedBy(-i)
let startIndex = endIndex.advancedBy(-length, limit: string.startIndex)
result.append(string[startIndex..<endIndex])
}
return result.reverse()
}
Or if you are feeling functional-y:
func splitedString2(string: String, length: Int) -> [String] {
return 0.stride(to: string.characters.count, by: length)
.reverse()
.map {
i -> String in
let endIndex = string.endIndex.advancedBy(-i)
let startIndex = endIndex.advancedBy(-length, limit: string.startIndex)
return string[startIndex..<endIndex]
}
}