What is the value in $t2?
LUI $t1, 0
ORI $t1, $t1, 16
LW $t2, 8($t1)
Firstly, I think that the equation is rs = offset + base address,
8 + 16 = 24.
However, my professor said it is wrong.
I think I do not fully understand LW. Could you help me to solve the problem and extra concept of LW?
$t1 = 0x10
$t2 = (0x18)
That is, the value stored at 0x18 will be loaded into $t2.
LW means Load Word. It loads a word into a register from the specified address. 0x18 is the address, not the value that will be stored into $t2.