As i'm trying to insert the value in database through php code but it didn't work and also it didn't give any error. Here is the code that i'd tried to execute but not succeeded.
<?php
$mysqli = new mysqli("localhost", "admin", "password", "project") or die("couldn't connect to the database");
error_reporting(0);
session_start();
if (!isset($_SESSION["sess_user"])) {
header("location:index.php");
} else {
$username = $_SESSION['sess_user'];
if (isset($_GET['submit'])) {
if ($_GET['e1'] == "E-LN3465") {
$productname = $mysqli->real_escape_string($_GET['e1']);
if ($insert = $db->query("INSERT INTO `cart`(`ID`, `pid`) ((Select `ID` from `users` where `Username`='$username'),(Select `pid` from `product` where `pname`='$productname'))")) {
$checkQuery = $mysqli->query("INSERT INTO `cart`(`ID`, `pid`) ((Select `ID` from `users` where `Username`='$username'),(Select `pid` from `product` where `pname`='$productname'))");
}
}
}
}
?>
In your code $mysqli
variable store your connection object and you are executing your query two time. $db
is nothing in your code just remove it
if ($mysqli->query("INSERT INTO `cart`(`ID`, `pid`) ((Select `ID` from `users` where `Username`='$username'),(Select `pid` from `product` where `pname`='$productname'))")) {
echo "INSERT SUCESSFULLY";
}
UPDATED
Change your query to
INSERT INTO `cart`(`ID`, `pid`)
SELECT users.ID, product.pid
FROM users, product
WHERE users.Username='$username'
AND product.pname='$productname';