I'm writing an application for iOS 7.0+
and I wanted to use new feature witch is: imageWithRenderingMode
. I have a map annotation with this code:
-(MKAnnotationView*)annotationView {
MKAnnotationView *annotationView = [[MKAnnotationView alloc] initWithAnnotation:self reuseIdentifier:@"AnnotationIdentifier"];
annotationView.enabled = YES;
annotationView.canShowCallout = YES;
annotationView.image = [[UIImage imageNamed:@"star"] imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];
annotationView.rightCalloutAccessoryView = [UIButton buttonWithType:UIButtonTypeDetailDisclosure];
annotationView.tintColor = [UIColor redColor];
return annotationView;
}
I was expected that my pins will be red, but stays black, only the callout (i) icon turns red.
I was trying to set self.view.tintColor
and self.mapView.tintColor
in my ViewController
but this not working either. How to turns this pins red?
There's a better solution than those proposed that doesn't involve creating a UIImageView
.
This Swift code will create a colored version of your UIImage
.
extension UIImage {
func colorized(color : UIColor) -> UIImage {
let rect = CGRectMake(0, 0, self.size.width, self.size.height);
UIGraphicsBeginImageContextWithOptions(rect.size, false, 0.0);
let context = UIGraphicsGetCurrentContext();
CGContextSetBlendMode(context, .Multiply)
CGContextDrawImage(context, rect, self.CGImage)
CGContextClipToMask(context, rect, self.CGImage)
CGContextSetFillColorWithColor(context, color.CGColor)
CGContextFillRect(context, rect)
let colorizedImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return colorizedImage
}
}
Call it like this:
UIImage(named: "myImage")!
.imageWithRenderingMode(.AlwaysTemplate)
.colorized(UIColor.red())