I need some help counting the rows and columns of a two dimensional array. It seems like I can't count columns?
#include <stdio.h>
int main() {
char result[10][7] = {
{'1','X','2','X','2','1','1'},
{'X','1','1','2','2','1','1'},
{'X','1','1','2','2','1','1'},
{'1','X','2','X','2','2','2'},
{'1','X','1','X','1','X','2'},
{'1','X','2','X','2','1','1'},
{'1','X','2','2','1','X','1'},
{'1','X','2','X','2','1','X'},
{'1','1','1','X','2','2','1'},
{'1','X','2','X','2','1','1'}
};
int row = sizeof(result) / sizeof(result[0]);
int column = sizeof(result[0])/row;
printf("Number of rows: %d\n", row);
printf("Number of columns: %d\n", column);
}
Output:
Number of rows: 10
Number of columns: 0
That's a problem of integer division!
int column = sizeof(result[0])/row;
should be
int column = 7 / 10;
and in integer division, 7/10==0.
What you want to do is divide the length of one row, eg. sizeof(result[0]) by the size of one element of that row, eg. sizeof(result[0][0]):
int column = sizeof(result[0])/sizeof(result[0][0]);