Im trying to rename a batch of files.
gulp.task('rename', ['jade'], function() {
gulp.src("public/build/*.html")
.pipe(rename(function (path) {
path.dirname += "/";
path.basename += "";
path.extname = ""
}))
.pipe(gulp.dest("public/build"));
gulp.src("public/build/story/*.html")
.pipe(rename(function (path) {
path.dirname += "/";
path.basename += "";
path.extname = ""
}))
.pipe(gulp.dest('public/build/story'));
gulp.src("public/build/work/*.html")
.pipe(rename(function (path) {
path.dirname += "/";
path.basename += "";
path.extname = ""
}))
.pipe(gulp.dest('public/build/work'));
});
This method finds the files I want to change and does the job, but it makes a entirely new files, and does not replace the old file. So im left with doubles of my batch, is there anything i should be adding to have this not happen?
I don't believe gulp-rename is supposed to replace your currently files, I am pretty sure it's supposed to just rename them and put them in a different directory. It's used when preparing an application for distribution. If you want to look into also removing files I would checkout out gulp-rimraf. github.com/robrich/gulp-rimraf