How do I generate a random number not including one without using a while loop?

Let's say I want to generate a random number between 1 and 100, but I don't want to include 42. How would I do this without repeating the random method until it is not 42.

Updated for Swift 5.1

Excluding 1 value

var nums = [Int](1...100)
nums.remove(at: 42)

let random = Int(arc4random_uniform(UInt32(nums.count)))
print(nums[random])

Excluding multiple values

This extension of Range does provide a solution when you want to exclude more than 1 value.

extension ClosedRange where Element: Hashable {
    func random(without excluded:[Element]) -> Element {
        let valid = Set(self).subtracting(Set(excluded))
        let random = Int(arc4random_uniform(UInt32(valid.count)))
        return Array(valid)[random]
    }
}

Example

(1...100).random(without: [40,50,60])

I believe the computation complexity of this second solution is O(n) where n is the number of elements included in the range.

The assumption here is the no more than n excluded values are provided by the caller.