How can I send plain text email (with line breaks) using sp_send_dbmail?

I have a SQL Server 2008 procedure that sends email via sp_send_dbmail.

I'm using the following code:

  set @bodyText = ( select 
                      N'Here is one line of text ' +
                      N'It would be nice to have this on a 2nd line ' +
                      N'Below is some data: ' +
                      N' ' +
                      N' ' +
                      field1 +
                      N' ' +
                      field2 +
                      N' ' +
                      N'This is the last line'
                    from myTable )

    EXEC msdb.dbo.sp_send_dbmail
        @profile_name = 'myProfile',
        @recipients = @to,
        @body = @bodyText,
        @body_format = 'TEXT',
        @subject = 'Testing Email' ;

My myProfile is set to use the local smtp server, which results in a .EML file in c:\inetpub\mailroot\queue

When I open one of those .eml files (ug - the only thing that can open them is outlook express, looking at them in anything else just shows the body as a base64 encoded blob.) it looks like it's rendering the result as HTML - so I'm not sure if the problem is in the client, or

I've tried putting \n into the message, but that didn't work. How can I send plain text with line breaks, and verify that the end result looks correct?

BTW, I can't actually send the email to test it with real email clients - corp. network is locked down.

You aren't actually inserting any line breaks. You can embed them directly in a string literal in SQL Server as below.

SET @bodyText = (SELECT N'Here is one line of text 
It would be nice to have this on a 2nd line 
Below is some data: 


' + field1 + N' 

' + field2 + N' 

' + N'This is the last line'
                 FROM   myTable);

Or a tidier approach might be

DECLARE @Template NVARCHAR(max) = 
N'Here is one line of text 
It would be nice to have this on a 2nd line 
Below is some data: 

##field1##

##field2##

This is the last line';

SET @bodyText = (SELECT REPLACE(
                    REPLACE(@Template, 
                       '##field1##', field1), 
                       '##field2##', field2)
                 FROM   myTable); 

Both will raise an error if myTable contains more than one row as you are assigning the result to a scalar variable.