I did some research on SO and am aware that many similar questions have been asked but I couldn't quite get my answer. Anyway, I'm trying to build a library to "encrypt" a string with "Cesar's number" technique which means I have to take the string and replace each letters with another letter X positions away in the alphabet (I hope that makes sense). Here's my code:
from string import ascii_lowercase, ascii_uppercase
def creer_encodeur_cesar(distance):
retour = lambda x: encodeur_cesar(x, distance)
return retour
def encodeur_cesar(string, distance):
tabLowerCase = list(ascii_lowercase)
tabUpperCase = list(ascii_uppercase)
tabString = list(string)
l_encodedStr = []
for char in tabString:
position = 0
if char == " ":
pass
elif char.isupper():
#do something
elif char.islower():
for ctl in range(0, len(tabLowerCase)):
position = ctl
if char == tabLowerCase[ctl]:
if (ctl + distance) > 26:
position = ctl + distance - 25
char = tabLowerCase[position + distance]
l_encodedStr.append(char)
#How to break out of here??
encodedStr = str(l_encodedStr)
return encodedStr
encodeur5 = creer_encodeur_cesar(5)
print(encodeur5("lionel"))
So, in my second elif statement, I want to break once I have successfully found and encrypted a character instead of looping through the whole alphabet. I have tried to use break but it broke out of the main for loop. Not what I want. I saw that I could use try except and raise but I don't quite know how I could do that and is it a good idea?
What's the best way to do this? What are the good practices in this case?
Any help would be appreciated and thanks in advance!
You can use the continue keyword.
From the docs:
>>> for num in range(2, 10):
... if num % 2 == 0:
... print "Found an even number", num
... continue
... print "Found a number", num
Found an even number 2
Found a number 3
Found an even number 4
Found a number 5
Found an even number 6
Found a number 7
Found an even number 8
Found a number 9