Issue about converting from char array to string - C++

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main () {
    string vet[10], aux;
    std::vector<char> name;
    int count=0, sum=0; 

    while (count<10) {
        getline(cin, aux);

        for (int i=0; i<aux.length(); i++)  name.push_back(aux[i]);

        for (int i=0; i<name.size(); i++) {
            name[i] = tolower(name[i]);                                 //para garantir que todos os caracteres estão em minúsculo  
            if (name[i] > 96 && name[i] < 123 && name[i] == 32)         //faixa de decimais das letras minúsculas e espaço em caso de nome composto
                sum += name[i];
        }

        char v[name.size()];                                            //vetor auxiliar criado para realizar a conversão de vetor de char para string

        for (int i=0; i<name.size(); i++)   {
            v[i] = name[i];
        }

        while (vet[sum%10] != "\0")                                     //para evitar colisão
            sum++;

        vet[sum%10] = (string) v;                                       //conversão para string e => K mod m = K % m em C++
        cout << vet[sum%10] << endl;
        count++;
        sum = 0;

        for (int i=0; i<name.size(); i++)   v[i] = '\0';

        name.clear();
    }

    cout << endl;

    for (int i=0; i<10; i++)    cout << vet[i] << endl;

    return 0;
}

This code is using the Hashing concept to store names inside of an array.

My question is:

Everytime that I try to insert a name with 8, 16 or 24 characters, while converting from char array to string, the compiler always put another 3 characters in front of them. If I try a name with 9, 17 or 25 characters, the compiler always put another 2 characters in front of them. And if I try a name with 10, 18 or 26 characters, the compiler always put another character in front of them.

Why does it happens? Is there a way to prevent it?

I need all the names to be exactly (but in lower case) as they were inserted on the input, but sorted according to the Hashing logic.

Thanks in advance!

The problem is here:

char v[name.size()];

As it was pointed out this is not standard C++ ...

Regardless, you can fix it like:

std::string v;    
v.resize(name.size());

More or less it has the same effect as your char array, except that it does not use a char array.